04-01-2007, 04:44 PM
Ok WELP I got 1 done. The last one. Since AFCE is a rhombus, all sides are the same length. so FC is also 16-x, and BC is 12 (it's a given). So you use the pythagorean thm. and the eq. is the square root of (16-x)(16-x)-144 which equals 32x=112 you divide 112 by 32 and get 3.5. So x is 3.5. Then, you use the pythagorean thm again (now you know the sides of the rhombus are all 12.5) to find EF. the equation is 12.5x12.5+12.5x12.5 and that ='s 312.5. Then you find the sq. root of that, which is about 17.67. <---that's the answer.
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